Answer: Our equation in point-slope form is
[tex]\frac{2x}{3}+\frac{14}{3}[/tex]
Explanation:
Since we have given that
there are two points i.e.
[tex](8,10)\ and\ (-4,2)[/tex]
Equation of point slope form :
[tex]y-y_0=m(x-x_0)\\\\where,\\\\m=\frac{y_2-y_1}{x_2-x_1}[/tex]
So, we will first calculate slope of tangent i.e. m
[tex]m=\frac{2-10}{-4-8}\\m=\frac{-8}{-12}\\m=\frac{2}{3}[/tex]
So, equation of line in point-slope form is
[tex](y-10)=\frac{2}{3}(x-8)\\\\3(y-10)=2(x-8)\\\\3y-30=2x-16\\\\3y-2x=-16+30\\\\3y-2x=14\\\\y=\frac{2x}{3}+\frac{14}{3}[/tex]
Hence, our equation in point-slope form is
[tex]\frac{2x}{3}+\frac{14}{3}[/tex]