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We dissolve 5.00 grams of sugar, C12H22O11, in water to make 1.000 L of solution. What is the concentration of this solution expressed as a molarity?

Respuesta :

mikaylasturns77
5 g C12H22O11/ 34g C12H22O11 = 0.01466
0.015mol / 1.000 L = 0.015 M

The most frequent way to describe the concentration of the solution is by molarity (M).  It is determined by the amount of solvent in moles divided by the volume of the solution in liters.

  • It's also known as molar concentration and seems to be the absorption of a suspension exposed as the number of solute particles per liter of solution.
  • Following are the calculation to the molarity:

          [tex]\to \frac{5\ g \ C_{12}H_{22}O_{11}}{34\ g \ C_{12}H_{22}O_{11}} = 0.01466\\\\\to \frac{0.015\ mol}{ 1.000\ L} = 0.015\ M[/tex]

Therefore, the answer is "0.015".

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