Answer:
[tex]\$14.18[/tex] Â
Step-by-step explanation:
we know that  Â
The compound interest formula is equal to Â
[tex]A=P(1+\frac{r}{n})^{nt}[/tex] Â
where Â
A is the Final Investment Value Â
P is the Principal amount of money to be invested Â
r is the rate of interest  in decimal
t is Number of Time Periods Â
n is the number of times interest is compounded per year
in this problem we have Â
[tex]t=10\ years\\ P=\$10\\ r=0.035\\n=12[/tex] Â
substitute in the formula above Â
[tex]A=P(1+\frac{0.035}{12})^{12*10}=\$14.18[/tex] Â