Respuesta :

bunnymarshmarloykw47
Refer to the notations above:

<BCD+40°=180° (angles on a strainght line)
<BCD=180°-40°
<BCD=140°

As BC=CD(given),△BCD is an isosceles triangle,thus <CBD=<CDB=x(properties of isosceles triangle).

We can then proceed to find x(<CDB and <CBD):

140°+ x + x=180°(angles sum of triangles)
2x=180°-140°
x=40°/2
x=20°

Then, we can again use the angles sum of triangle to solve y:

y+90°+20°=180°
y=180°-90°-20°
y=70°

Therefore, x=20° and y=70°.

Hope it helps!
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